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#maths

49 posts37 participants0 posts today

I'll be posting the questions from AMS 2025 Daily Epsilon of Math Calendar daily from now on. I should have started earlier (doing it on Blue sky for some time). Hope it will be of interest

Here's the question for April 15th. For those unfamiliar with the calendar, the answer is always the day of the month. Looking for imaginative solutions is the aim.

Bonjour Mastodon ! Une courte #introduction après avoir passé un bon moment en observateur 👀.

Je viens des #Maths appliquées, et continue à m’intéresser aux sujets liés à la tech, quand elle me semble politiquement émancipatrice : #LowTech, #DIY, #LogicielLibre, #DonnéesOuvertes, etc.

Au quotidien, beaucoup de temps passé à farfouiller de la #Musique, un peu de #Cyclisme et de la #Cuisine 🤤

Mes pronoms : il/lui

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Hello Mastodon!

A brief #Introduction post after some time as a fediverse observer 👀.

I come from applied #Maths, and am still quite interested in related tech topics when they lead to more freedom and emancipation: #LowTech, #DIY, #FreeSoftware, #OpenSourceSoftware, #OpenData, etc.

In everyday life, a lot of my time is spent digging (and sometimes playing) some #Music, a bit of #Cycling, and #Cooking 🤤

My pronouns: he/him

My son pulled out a textbook at his tutoring centre and asked me to do this question.

Moving past the odd statement that the object is at rest when the forces aren't balanced, when I resolve the weight of the I get a net force along the slope of 2N, assuming a friction coefficient of 0.

The friction coefficient would need to be greater than 1 for the object to be at rest with the initial applied forces.

Textbook says the answer is 0. Am I missing something? #maths #mechanics

I'll be posting the questions from AMS 2025 Daily Epsilon of Math Calendar daily from now on. I should have started earlier (doing it on Blue sky for some time). Hope it will be of interest

Here's the question for April 14th. For those unfamiliar with the calendar, the answer is always the day of the month. Looking for imaginative solutions is the aim.

#MathsMonday
#Chinese #Maths #Math #Mathematics
I've seen this video a couple of times, but I never saw any explanation.... so I decided to work it out for myself how they did that! 🙂 Feel free to watch it and see if you can work it out yourself, but if you can't (or don't want to), then here's how this works (scroll down for reveal)...

First some pronumerals, then the steps - a=97, b=94, c=3, d=6
- c=100-a
- d=100-b
- the first 2 digits is a-d
- the last 2 digits is cxd

I'll be posting the questions from AMS 2025 Daily Epsilon of Math Calendar daily from now on. I should have started earlier (doing it on Blue sky for some time). Hope it will be of interest

Here's the question for April 13th. For those unfamiliar with the calendar, the answer is always the day of the month. Looking for imaginative solutions is the aim.

someone dropped off a buyers remorse donation of coloured pencils for the #colouring2cope group i put together and accidentally made and extra point abouts #capitalism #maths...

2boxes of perceived product equals 1box of actual product and 1box of waste

...no worries, ill boil all those down to make canvas boards for expressing on... but the point remains.